G4VHD

I'd be up for that around August/September time if we can get enough....coming from midlands my self

Plus the 2ld is an amazing engine...I know, i have one with 115k, its a beast ask Andy-mcq ;)

You have a E46 Andy... 2k aint too cheap with them miles, some people dont realise BMW milage potential! With full BMWSH, its got to be looked after as there service prices are madness

Welcome along mate

Welcome along mate

Use the 325 loom?

Can you post a close up pic of one of the c/caps mate please

No Steve...Please...DONT

Welcome along Bob

Passed, no advisories either :D:D

Sat the 23rd this month mate

First one under my ownership tomorrow... I hope nothing serious pops up....:huh:

Welcome along mate :D

Night caz

Dabsy's secret lover

I got it right

(3x-2)(x+1)=0 x=2/3 x=-1

Kinky gimp thongs

Welcome along, Im sure we have a wanted section on this forum somewhere mate

x2-3x+2=0 [x^2-2X(3/2)X(x)]+2=0 Notice that the first two terms have been brought under the structure a^2 -2ab. So you need b^2 to complete the square and here b^2-(3/2)^2 = 9/4 Therefore [x^2-2X(3/2)X(x)+(9/4-9/4)]+2=0 [x^2-2X(3/2)X(x)+(9/4]+(-9/4+2)=0 (x-3/2)^2 = 9/4-2 = 1/4 Taking the sqroot (x-3/2)= +1/2 or -1/2 (x-3/2)= +1/2 gives x = 1/2+3/2 = 2 (x-3/2)= -1/2 gives x = -1/2+3/2 = 1 Answer: x = 2 and x=1 solve by using the quadratic equasion x2-3x+2=0 x2+[(-2x)+(-x)]+2=0 [splitting the middle term into two parts whose multiplication is the product of the square term and the constant term. -3x = (-2x) + (-x) so that (-2x)X(-x) = +(2x^2) = (x^2)X(2)] x2-2x-x+2=0 (x2-2x)-x+2=0 x(x-2)-(x-2)=0 xp-p=0 where p = (x-2) p(x-1) = 0 (x-2)(x-1) = 0 (x-2) = 0 gives x = 2 and (x-1) = 0 gives x = 1

48 / 2(9+3) = ????

I aint :D

Lol :D

Na

It dont B)